Answer:
Option D.
[tex]x\geq -2[/tex] or [tex]x\leq -6[/tex]
Step-by-step explanation:
The correct question in the attached figure
we have
[tex]3x+5\geq -1[/tex] ----> inequality A
subtract 5 both sides
[tex]3x\geq -1-5[/tex]
[tex]3x\geq -6[/tex]
divide by 3 both sides
[tex]x\geq -2[/tex]
The solution of the inequality A is the interval [-2,∞)
[tex]-2x-7\geq 5[/tex] ----> inequality B
adds 7 both sides
[tex]-2x\geq 5+7[/tex]
[tex]-2x\geq 12[/tex]
divide by -2 both sides
Remember that when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol
[tex]x\leq -6[/tex]
The solution of the inequality B is the interval (-∞,-6]
therefore
The solution of the system is
[tex]x\geq -2[/tex] or [tex]x\leq -6[/tex]