Respuesta :

Answer:

Option D.

[tex]x\geq -2[/tex]  or  [tex]x\leq -6[/tex]

Step-by-step explanation:

The correct question in the attached figure

we have

[tex]3x+5\geq -1[/tex] ----> inequality A

subtract 5 both sides

[tex]3x\geq -1-5[/tex]

[tex]3x\geq -6[/tex]

divide by 3 both sides

[tex]x\geq -2[/tex]

The solution of the inequality A is the interval [-2,∞)

[tex]-2x-7\geq 5[/tex] ----> inequality B

adds 7 both sides

[tex]-2x\geq 5+7[/tex]

[tex]-2x\geq 12[/tex]

divide by -2 both sides

Remember that when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

[tex]x\leq -6[/tex]

The solution of the inequality B is the interval (-∞,-6]

therefore

The solution of the system is

[tex]x\geq -2[/tex]  or  [tex]x\leq -6[/tex]

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