Question

what mass of water would you need to have 15.0 moles of h2o?

Answer 1

Answer:

270 g H₂O

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table

Stoichiometry

• Using Dimensional Analysis

Explanation:

Step 1: Define

15.0 mol H₂O

Step 2: Identify Conversions

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

1. Set up:                              $\displaystyle 15.0 \ mol \ H_2O(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})$
2. Multiply/Divide:                $\displaystyle 270.3 \ g \ H_2O$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

270.3 g H₂O ≈ 270 g H₂O