Answer:
The rain drop of mass 0.050 g has 0.0028 moles of water.
Explanation:
We know that for each element or compound the molar mass of that compound is equal to 1 mole of that compound. So in the present case, the molar mass of water can be determined as sum of mass of two hydrogen atoms and one oxygen atom. Thus, the molar mass of water is found to be 18.01 g.
Since, 18.01 g of water = 1 mole of water
Then, 1 g of water = 1/18.01 mole of water.
But, here it is given that the raindrop contains 0.050 g of water, then
0.050 g of water = 0.050×[tex]\frac{1}{18.01}[/tex] moles = 0.0028 moles of water.
Thus, the rain drop of mass 0.050 g has 0.0028 moles of water.
