Answer:
[tex] lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V} =\infty[/tex]
This limit is not defined.
Explanation:
We need to remember first this law
The Boyle's law states that under a constant temperature when the pressure is inversely proportion to the volume.
So that means: [tex] P \propto \frac{1}{V}[/tex]
And we can put an equal if we do this:
[tex] P = \frac{k}{V}[/tex] where k is the proportional constant.
For this case we want to find the following limit:
[tex] lim_{V \to 0^{+}} P = \lim_{V \to 0^{+}} \frac{k}{V}[/tex]
And using properties of limits we have:
[tex] lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V}[/tex]
So for this case this limit tend to infinity since we are dividing a constant by a very low number positive near to 0.
So then we can conclude that:
[tex] lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V} =\infty[/tex]
This limit is not defined.
Interpretation: we are seeing that if the volume decrease considerable with the temperature constant by the inverse relation between P and V, the value of P increases to with no limit.