Question

How much charge q 2 q2 does the rod have? Model the balloon and rod as point charges. The Coulomb force constant is 1 / ( 4 π ϵ 0 ) = 8.99 × 10 9 1/(4πϵ0)=8.99×109 N·m2/C2, and the acceleration due to gravity is g = 9.81 g=9.81 m/s2.

Answer 1

Answer:

The value of second charge is $3.575\times10^{-7}\ C$

Explanation:

Suppose A 0.00260-kilogram air inflated balloon is given an excess negative charge, $q_{1}=-3.25\times10^{-8}\ C$, by rubbing it with a blanket. It is found that a charged rod can be held above the balloon at a distance of d = 0.0640 m to make the balloon float.

Given that,

Mass =0.00260 kg

Charge $q_{1}=-3.25\times10^{-8}\ C$

Distance = 0.0640 m

We need to calculate the force

Using newton's second law

$F = mg$

Put the value in to the formula

$F=0.00260\times 9.81$

$F=0.025506\ N$

We need to calculate the value of second charge

Using formula of electric force

$F=\dfrac{kq_{1}q_{2}}{r^2}$

Put the value into the formula

$0.025506=\dfrac{8.99\times10^{9}\times3.25\times10^{-8}\times q_{2}}{(0.0640)^2}$

$q_{2}=\dfrac{0.025506\times(0.0640)^2}{8.99\times10^{9}\times3.25\times10^{-8}}$

$q_{2}=3.575\times10^{-7}\ C$

Hence, The value of second charge is $3.575\times10^{-7}\ C$