Answer:
The car will travel a distance of 17.45 meters.
Explanation:
Given:
Initial velocity [tex](V_i)[/tex] = 0
Final velocity [tex](V_f)[/tex] = 7.6 m/s
Time taken = 4.6 s
Acceleration = (Final velocity - Initial Velocity )/time
[tex]a=\frac{(V_f-Vi)}{t}= \frac{7.6-0}{4.6}=1.65\ ms^-2[/tex]
We have to calculate total distance traveled by the car.
Let the distance traveled be 'd'
Equation of motion:
[tex]d=V_i(t)+\frac{at^2}{2}[/tex]
Plugging the values.
⇒[tex]d=V_i(t)+\frac{at^2}{2}[/tex]
⇒[tex]d=0+\frac{1.65*(4.6)^2}{2}[/tex]
⇒[tex]d=17.45\ m[/tex]
The car will travel a distance of 17.45 meters for the above case.
