Two car wash employees are paid $7.50 an hour each and are capable of washing 12 cars per hour, using $1 of water and $2 of soap and other cleaning supplies. What is the multifactor productivity of this operation?

0.66 cars per dollar
1.05 dollars per car
0.95 cars per dollar
1.8 dollars per car

Respuesta :

Answer:

Option A.

Step-by-step explanation:

Given information: Number of employees = 2, Number of hours = 1

Number of car =  12, Cost of water = $1, Cost of Soap = $2

Salary of each employee = $7.50 each hour

Using these information we get

Salary of 2 employees = $15 each hour

[tex]\text{Multifactor productivity}=\dfrac{Outp ut}{Inp ut}[/tex]

Output = 12 cars

Input = $15 + $1 + $2 = $18

[tex]\text{Multifactor productivity}=\dfrac{12}{18}[/tex]

[tex]\text{Multifactor productivity}=0.6666..[/tex]

[tex]\text{Multifactor productivity}\approx 0.66[/tex]

The multifactor productivity of this operation is 0.66 cars per dollar.

Therefore, the correct option is A.

The required Multifactor productivity of this operation is 0.66 cars per dollar.

Given that,

Number of wash employees = 2,

Number of hours = 1

Number of  capable of washing car =  12,

Cost of water = $1,

Cost of Soap = $2

Salary of each employee = $7.50 each hour

We have to find,

The multifactor productivity of this operation.

According to the question ,

Salary of 2 employees = salary of each employee × 2 = $7.5 × 2 = $15 each hour.

Multifactor productivity = output ÷ input

Total no. cars Output = 12 cars

Input = $15 + $1 + $2 = $18

Multifactor productivity = [tex]\frac{12}{18}[/tex]

Multifactor productivity = 0.66

Hence, The required Multifactor productivity of this operation is 0.66 cars per dollar.

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