A 36 kg child sits in a swing supported by two chains, each 2.9 m long. If the tension in each chain at the lowest point is 265 N, find the child’s speed at the lowest point. (Neglect the mass of the seat.) Answer in units of m/s.

Respuesta :

Answer:

v = 3.78 m/s

Explanation:

given,

mass of the child = 36 Kg

length of the chain, r = 2.9 m

tension in each chain, T = 265 N

now,

Net force acting in the system

2 T - m g = m a

T is the tension in the chain

a is the acceleration in the normal direction

here, [tex]a = \dfrac{v^2}{r}[/tex]

now,

[tex]2 T - m g = m\dfrac{v^2}{r}[/tex]

[tex]2\times 265 - 36\times 9.8 = 36\times \dfrac{v^2}{2.9}[/tex]

          v² = 14.274

          v = 3.78 m/s

speed of the child at the lowest point is equal to 3.78 m/s