Answer:
v = 3.78 m/s
Explanation:
given,
mass of the child = 36 Kg
length of the chain, r = 2.9 m
tension in each chain, T = 265 N
now,
Net force acting in the system
2 T - m g = m a
T is the tension in the chain
a is the acceleration in the normal direction
here, [tex]a = \dfrac{v^2}{r}[/tex]
now,
[tex]2 T - m g = m\dfrac{v^2}{r}[/tex]
[tex]2\times 265 - 36\times 9.8 = 36\times \dfrac{v^2}{2.9}[/tex]
v² = 14.274
v = 3.78 m/s
speed of the child at the lowest point is equal to 3.78 m/s