The question is incomplete, here is the complete question:
How many milliliter of concentrated nitric acid, 16 M are required to prepare 500 mL of 0.5 M [tex]HNO_3[/tex]
Answer: The volume of concentrated nitric acid solution required is 15.625 mL
Explanation:
To calculate the molarity of the diluted solution, we use the equation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the concentrated nitric acid solution
[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted nitric acid solution
We are given:
[tex]M_1=16M\\V_1=?mL\\M_2=0.5M\\V_2=500mL[/tex]
Putting values in above equation, we get:
[tex]16\times V_1=0.5\times 500\\\\V_1=\frac{0.5\times 500}{16}=15.625mL[/tex]
Hence, the volume of concentrated nitric acid solution required is 15.625 mL