Respuesta :

The question is incomplete, here is the complete question:

How many milliliter of concentrated nitric acid, 16 M are required to prepare 500 mL of 0.5 M [tex]HNO_3[/tex]

Answer: The volume of concentrated nitric acid solution required is 15.625 mL

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the concentrated nitric acid solution

[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted nitric acid solution

We are given:

[tex]M_1=16M\\V_1=?mL\\M_2=0.5M\\V_2=500mL[/tex]

Putting values in above equation, we get:

[tex]16\times V_1=0.5\times 500\\\\V_1=\frac{0.5\times 500}{16}=15.625mL[/tex]

Hence, the volume of concentrated nitric acid solution required is 15.625 mL

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