Question

Calculate the specific
heat capacity of substance having mass 5 kg whose
temperature increase from 15°C to 25°C by the supply of
19 KJ​

Answer 1

Answer: c= 0.38 J/ g °C

Explanation: Use the equation Q= mcΔT and derive to solve for c.

c = Q / mΔT

First convert 19 KJ  to joules

19 kJ x 1000 J / 1 kJ = 19000 J

Then convert 5 kg to grams

5 kg x 1000 g / 1 kg = 5000 g

After that substitute the following variables into the equation.

c= 19000 J / 5000 g ( 25 - 15 ) = 0.38 J/ g°C