Question

-3i^2(-4root+5)+i^3,in simplest a+bi form

Answer 1

Answer:

Step-by-step explanation:

$-3i^{2}(\sqrt{-4}+5)+i^{3}=-3*-1(i\sqrt{4}+5)+(-i)\\\\=-3(i\sqrt{4}+5)-i\\\\=-3*i\sqrt{4}+(-3)*5-i\\\\=-3i\sqrt{4}-15-i\\\\=-i(3\sqrt{4}+1)-15$

i^2 = -1

i^3 = -i