Question

A golfer, driving a golf ball off the tee, gives the ball a velocity of 38 m/sec. The mass of the ball is 0.045 kg, and the duration of the impact with the golf club is 0.003 sec.
(a) What is the change in momentum of the ball?

Answer 1

Answer:

$\Delta p=1.71\frac{kg\cdot m}{s}$

Explanation:

The momentum of a body is defined as the product of its mass and its velocity at a given time. Therefore the change in the momentum of the ball is given by the difference between the final momentum and the initial momentum:

$\Delta p=p_f-p_i\\\Delta p=mv_f-mv_i\\\Delta p=m(v_f-v_i)\\\Delta p=0.045kg(38\frac{m}{s}-0\frac{m}{s})\\\Delta p=1.71\frac{kg\cdot m}{s}$

Answer 2

the change in momentum of the ball is 1.71 kgm/s

To calculate the change in momentum of the gulf ball, we use the formula below.

Formula:

• ΔM = m(v-u).............. Equation 1

Where:

• ΔM = Change in momentum of the ball
• m = mass of the ball
• v = final velocity of the ball
• u = Initial velocity of the ball.

From the question,

Given:

• m = 0.045 kg
• v = 38 m/s
• u = 0 m/s.

Substitute these values into equation 1

• ΔM = 0.045(38-0)
• ΔM = 0.045×38
• ΔM = 1.71 kgm/s

Hence, the change in momentum of the ball is 1.71 kgm/s

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