Answer:
0.81 atm will be the new pressure.
Explanation:
This is the formula to solve this:
P₁ / T₁ = P₂ / T₂
1.03 atm / (28°C + 273) = P₂ / (-35°C + 273)
1.03 atm / 301K = P₂ / 238K
(1.03 atm / 301K) . 238K = 0.81 atm
The gas pressure is directly proportional to its absolute temperature when the volume keeps on constant.
Answer:
The new pressure at the new temperature 238 K, is 0.814 atm
Explanation:
Step 1: Data given
Volume = 1.43 L
Temperature = 28°C
Total pressure = 1.03 atm
The temperature drops to -35 °C
The volume stays constant ( = 1.43 L)
Step 2: Calculate the new pressure
P1/T1 = P2/T2
⇒ with P1 = The initial pressure = 1.03 atm
⇒ with T1 = the initial temperature = 28 °C = 301 K
⇒ with P2 = The final pressure = ?
⇒ with T2 = The final temperatures = -35 °C = 238 K
1.03 / 301 = P2 / 238
P2 = (1.03*238)/301
P2 = 0.814 atm
The new pressure at the new temperature 238 K, is 0.814 atm
