Answer:
A MCAT score that is significantly high is a score of at least 38.
A MCAT score that is significantly low is at most 12.4.
Step-by-step explanation:
The z-score formula is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
In which [tex]\mu[/tex] is the mean and [tex]\sigma[/tex] is the standard deviation.
In this problem, we have that:
[tex]\mu = 25.2, \sigma = 6.4[/tex]
Significantly high if it has a zscore of at least 2
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]2 = \frac{X - 25.2}{6.4}[/tex]
[tex]X - 25.2 = 2*6.4[/tex]
[tex]X = 38[/tex]
A MCAT score that is significantly high is at least 38.
Significantly low if it has a score of at most - 2
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-2 = \frac{X - 25.2}{6.4}[/tex]
[tex]X - 25.2 = -2*6.4[/tex]
[tex]X = 12.4[/tex]
A MCAT score that is significantly low is at most 12.4.