Question

If it takes 10.0 kJ of heat to raise the temperature of 100.0g if a substance by 50°C, what is the specific heat of the substance?

Answer 1

Answer:

2.0 J/g°C

Explanation:

We are given;

• Quantity of heat as 10.0 kJ
• Mass of the substance as 100 g
• Temperature change is 50°C

We are required to calculate the specific heat capacity of the substance;

• We need to know that the quantity of heat gained by a substance is given by;

Quantity of heat = Mass × specific heat × change in temperature

That is;

Q = mcΔT

Rearranging the formula;

c = Q ÷ mΔT

Therefore;

c = 10000 J ÷ (100.0 g × 50°C)

  = 2.0 J/g°C

Thus, the specific heat of the substance is 2.0 J/g°C