Question

Given is a linear Equation 1 in the format of y = mx + b.

Equation 1, y = 46,888 + 0.78x

Plot Equation 1 on a graph paper. Label all axes and markers on the graph.

Answer 1

Answer: The graph is attached.

Step-by-step explanation:

The equation of a line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

In order to graph the given line, you can find the x-intercept and the y-interecept.

Knowing that the equation of that line in Slope-Intercept form is:

$y = 46,888 + 0.78x$

You can identify that the slope of the line is:

$m= 0.78$

And the y-intercept is:

$b=46,888$

The line intersects the x-axis when $y=0$, then, substituting this into the equation and solving for "x", you get that the x-intercept is:

$0 = 46,888 + 0.78x\\\\-46,888=0.78x\\\\\frac{-46,888}{0.78}=x\\\\x=-60,112.82$

Therefore, knowing that the line passes trough the points $(0,\ 46,888)$and $(-60,112.82\ ,0)$ you can graph it.

The graph is attached.