[tex]\boxed{y-5=-\frac{1}{7}(x-4)}[/tex]
As I understand you need the equation of the line that passes through the point [tex](4,5) \ and \ (11,4)[/tex], So the point-slope form of the equation of a line is given by:
[tex]y-y_{1}=m(x-x_{1}) \\ \\ \\ Where: \\ \\ (x_{1},y_{1}):A \ point \ on \ the \ line \\ \\ m:Slope[/tex]
So:
[tex]y-y_{1}=m(x-x_{1}) \\ \\ \\ m=\frac{4-5}{11-4} \\ \\ m=-\frac{1}{7} \\ \\ \\ So: \\ \\ y-5=-\frac{1}{7}(x-4)[/tex]
Parallel lines: https://brainly.com/question/12169569
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