Respuesta :

Answer:

Therefore the Equation and missing value is

[tex]\dfrac{3}{4}=\dfrac{1}{6}+x[/tex]      .............Equation for the Diagram

[tex]x=\dfrac{7}{12}[/tex]

Step-by-step explanation:

Given:

Let Label the Diagram such that

[tex]AB =\dfrac{1}{6}[/tex]

[tex]BC =c[/tex]

[tex]AC =\dfrac{3}{4}[/tex]

To Find:

Equation =?

x = ?

Solution:

Here Total Length is given in Two Parts

[tex]one\ part =\dfrac{1}{6}[/tex]

[tex]Second\ part =x[/tex]

[tex]Total =\dfrac{3}{4}[/tex]

For a Line A-B-C

[tex]AC =AB+BC[/tex]       ..............Line Addition Property

Substituting the values we get

[tex]\dfrac{3}{4}=\dfrac{1}{6}+x[/tex] ...Equation for the Diagram

[tex]x = \dfrac{3}{4}-\dfrac{1}{6}\\\\x=\dfrac{18-4}{4\times 6}\\\\x=\dfrac{14}{24}\\\\x=\dfrac{7}{12}[/tex]

Therefore the Equation and missing value is

[tex]\dfrac{3}{4}=\dfrac{1}{6}+x[/tex] ...Equation for the Diagram

[tex]x=\dfrac{7}{12}[/tex]

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