The total cost of 6 white chocolate pretzels and one dark chocolate pretzel is $5.75
Step-by-step explanation:
Let,
Cost of one white chocolate pretzel = x
Cost of one dark chocolate pretzel = y
According to given statement;
4x+6y=$10.50 Eqn 1
8x+3y=$9.75 Eqn 2
Multiplying Eqn 1 by 2
[tex]2(4x+6y=$10.50 )\\8x+12y=21\ \ \ Eqn\ 3[/tex]
Subtracting Eqn 2 from Eqn 3
[tex](8x+12y)-(8x+3y)=21-9.75\\8x+12y-8x-3y=11.25\\9y=11.25[/tex]
Dividing both sides by 9
[tex]\frac{9y}{9}=\frac{11.25}{9}\\y=1.25[/tex]
Putting y=1.25 in Eqn 1
[tex]4x+6(1.25)=10.50\\4x+7.50=10.50\\4x=10.50-7.50\\4x=3[/tex]
Dividing both sides by 4
[tex]\frac{4x}{4}=\frac{3}{4}\\x=0.75[/tex]
Cost of 6 white chocolate pretzels and one dark chocolate pretzel = 6x+y
Cost of 6 white chocolate pretzels and one dark chocolate pretzel = 6(0.75)+1.25 = $5.75
The total cost of 6 white chocolate pretzels and one dark chocolate pretzel is $5.75
Keywords: linear equation, elimination method
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