Question

A horizontal force of 120 N is required to push a bookcase across the floor at a constant velocity how much is the friction force that acts on the sliding bookcase

Answer 1

The Friction Force that acts on a sliding bookcase is -120 N

Explanation:

• Frictional force is the force developed by the two surfaces where they contact and slide against each other. They mainly affected by amount of force impelled them together and by the angle and position of the object.
•             Frictional Force F = Coefficient of friction * normal force

• At a constant velocity, there will be no acceleration and the net force will be zero.

               Net Force        = m * a = 0

               120 - Friction   = 0

               Friction Force  = -120 N

Answer 2

The friction force that acts on the sliding case is 120 N.

What is frictional force:

This is the force that opposes the motion of two bodies in contact. The s.i unit of frictional force is Newton (N).

The formula to calculate the friction of the bookcase is given below

Formula:

• F' = F-ma............ Equation 1

Where:

• F' = Friction force acting on the bookcase
• F = Horizontal force required to push the bookcase
• m = mass of the bookcase
• a = acceleration of the bookcase

From the question,

Given:

• F = 120 N
• m = unknown = x kg
• a = 0 m/s² (moving with constant velocity)

Substitute these values into equation 1

• F' = 120-x(0)
• F' = 120-0

• F' = 120 N

Hence, the friction force that acts on the sliding case is 120 N.

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