Question

A mixture of gases has 0.3000 mol of CO2, 0.2706 mol of SO2 and 0.3500 mol of water vapor. The total pressure of the mixture is 1.500 atm. What is the partial pressure of SO2 in atm?

Answer 1

Answer:

Partial pressure SO₂ → 0.440 atm

Explanation:

We apply the mole fraction concept to solve this:

Moles of gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 0.3 moles of CO₂ + 0.2706 moles of SO₂ + 0.35 moles H₂O

Total moles = 0.9206 moles

Mole fraction SO₂ = 0.2706 moles / 0.9206 moles → 0.29

Now, we can know the partial pressure:

0.29 = Partial pressure SO₂ / Total pressure

0.29 = Partial pressure SO₂ / 1.5 atm

0.29 . 1.5atm = Partial pressure SO₂ → 0.440 atm

Answer 2

The pressure exerted by the particular gas in a system when alone is partial pressure. The partial pressure of the sulfur dioxide will be 0.440 atm.

What is partial pressure?

The partial pressure of the gas is the amount of pressure it exerts on the walls of the system when alone.

Using the mole fraction the amount of the partial pressure can be calculated as:

$\dfrac{\text{Moles of gas}}{\text{Total moles}} = \dfrac{\text{Partial pressure of the gas}}{\text{Total pressure}}$

The total moles of the gas present is calculated as:

0.3 moles of carbon dioxide + 0.2706 moles of sulphur dioxide + 0.35 moles water = 0.9206 moles

Using the mole fraction formula the partial pressure of the gas is:

$\begin{aligned} \text{Partial pressure of gas} &= \dfrac{\text{Moles of gas}}{\text{Total moles}} \times \text{Total pressure}\\\\&= \dfrac{0.2706}{0.9206}\times 1.5\\\\&= 0.440\;\rm atm\end{aligned}$

Therefore, 0.440 atm is the partial pressure of the sulphur dioxide gas.

Learn more about partial pressure here:

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