The present age of Jane is 45 years old and present age of her sister is 9 years old
Solution:
Let the present age of Jane be "x"
Let the present age of her sister be "y"
Jane is 5 times older than her sister
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
In 3 years, Jane’s sister will be 1/4 her age
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)
[tex]3 + y = \frac{1}{4}(3 + x)[/tex]
Substitute eqn 1 in above equation
[tex]3 + y = \frac{1}{4}(3 + 5y)\\\\12 + 4y = 3 + 5y\\\\5y - 4y = 12 - 3\\\\y = 9[/tex]
Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
