Answer:
a) [tex]t=\sqrt{\frac{d}{4.9}}[/tex]
b) [tex]t=0.25 s[/tex]
Step-by-step explanation:
a) We have the following equation:
[tex]t=\sqrt{\frac{2d}{9.8}}[/tex] (1)
Where [tex]t[/tex] is the time is seconds, [tex]d[/tex] is the distance in meters and [tex]9.8 m/s^{2}[/tex] is the acceleration due gravity
If we divide numerator and denominator inside the square root by 2:
[tex]t=\sqrt{\frac{2d/2}{9.8/2}}[/tex]
We will have:
[tex]t=\sqrt{\frac{d}{4.9}}[/tex]
Hence:
[tex]?=4.9[/tex]
b) Using the same equation (1) with thw following data:
[tex]d=32 cm \frac{1 m}{100 cm}=0.32 m[/tex]
[tex]t=\sqrt{\frac{2(0.32 m)}{9.8 m/s^{2}}}[/tex]
We will have the reaction time:
[tex]t=0.25 s[/tex]
