Question

An electrical contractor's records during the last five weeks indicate the number of job requests: Week 1 2 3 4 5 Requests 20 22 18 21 22. Predict the number of requests for Week 6 using each of these methods: (a). Naive. (b). A four-period moving average. (c). weighted moving average using 0.50 for week 5, 0.30 for week 4, and 0.20 for week 3. (D). Exponential smoothing with alpha=.30. use 20 for week 2 forecast.

Answer 1

Answer:

Please see attachment

Explanation:

Please see attachment

Answer 2

The number of requests by giving the given forecasting methods are given below:

(a). Naive  = 22,

(b). A four-period moving average = 20.75

(c). Weighted moving average = 20.9, and,

(d). Exponential smoothing with alpha is .30  = 20.72

What is the method of nave forecasting?

Nave forecasting is the estimating method in which the last years' actual data are used to forecast the current actual, without attempting to show the simple elements.

Computation of a number of requests by:

(a). Nave Method of Forecasting:

Nave for the 6th week is 22 because in week 5 it's 22, so therefore, according to the previous week, the request for the 6th month is also 22.

(b). Four-period moving average:

$\text{four-Period Moving Average}= \dfrac{week 5+ week 4+ week3+ week 2}{4}\\\\\text{four-Period Moving Average}=\dfrac{22+21+18+22}{4}\\\\\text{four-Period Moving Average}=20.75$

(c). Weighted moving Average:

Using the given information in the above problem, the value of requests are:

$\text{Weighted Moving Average} = (0.50 \times 22)+(0.30 \times 21)+(0.20 \times 18)\\\text{Weighted Moving Average} = 20.9$

(d). Exponential smoothing using the alpha 0.30:

$\text{Exponential Smoothing Using the Alpha 0.30} = 20.17+(0.30 \times 21)+ (0.20\times 18)\\\text{Exponential Smoothing Using the Alpha 0.30} = 20.72$

Therefore, the exponential smoothing alpha is 20.72.

Learn more about Nave forecasting, refer to:

https://brainly.com/question/1855379