A bullet is fired into the air with an initial velocity of 1000 feet per second at an angle of 75o from the horizontal. The horizontal and vertical components of the velocity vector are:

Respuesta :

Answer

given,

initial velocity of the bullet = 1000 ft/s

angle made with horizontal = 75°

the horizontal and vertical component of the velocity = ?

Horizontal component of the velocity

 [tex]v_h = v cos \theta[/tex]

 [tex]v_h = 1000 cos 75^0[/tex]

 [tex]v_h =258.82\ m/s[/tex]

vertical component of the velocity

 [tex]v_v = v sin \theta[/tex]

 [tex]v_v = 1000 sin 75^0[/tex]

 [tex]v_v =965.93\ m/s[/tex]

The horizontal and vertical component of the bullet is equal to   [tex]v_h =258.82\ m/s[/tex] and   [tex]v_v =965.93\ m/s[/tex] respectively.

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