Answer
given,
initial velocity of the bullet = 1000 ft/s
angle made with horizontal = 75°
the horizontal and vertical component of the velocity = ?
Horizontal component of the velocity
[tex]v_h = v cos \theta[/tex]
[tex]v_h = 1000 cos 75^0[/tex]
[tex]v_h =258.82\ m/s[/tex]
vertical component of the velocity
[tex]v_v = v sin \theta[/tex]
[tex]v_v = 1000 sin 75^0[/tex]
[tex]v_v =965.93\ m/s[/tex]
The horizontal and vertical component of the bullet is equal to [tex]v_h =258.82\ m/s[/tex] and [tex]v_v =965.93\ m/s[/tex] respectively.