Respuesta :
Answer:
F = 7500 N
Explanation:
given,
mass of the car, m = 1200 Kg
initial speed of the car, v = 25 m/s
final speed of car = 0 m/s
time in which car is at rest, t = 5 s
distance = 50 m
Force = ?
using equation of motion for the calculation of acceleration.
v² = u² + 2 a s
0² = 25² + 2 x a x 50
100 a = -625
a = - 6.25 m/s²
negative sign shows deceleration of the car
now, force calculation
F = m a
F = 1200 x 6.25
F = 7500 N
hence, net force is equal to F = 7500 N
The horizontal net force required to bring the car to a halt at a distance of 50 m is 7500 N.
Net Force
The net force is calculated by the vector sum of all the forces applied to an object.
Given that the mass m of the car is 1.20x10^3 kilogram and the initial speed u is 25 meters per second. The total distance d is 50 m. The final speed v of the car is 0 m/s.
The acceleration a can be calculated by the equation of motion.
[tex]v^2 = u^2 +2ad[/tex]
Substituting the values in the above equation.
[tex]0^2 = 25^2 +2\times a\times 50[/tex]
[tex]a = \dfrac{-625 }{100}[/tex]
[tex]a = -6.25 \;\rm m/s^2[/tex]
The car has a deacceleration which is shown by the negative sign of the acceleration.
The net force on the car is given below.
[tex]F = m\times a[/tex]
[tex]F = 1.20\times 10^3 \times 6.25[/tex]
[tex]F = 7500\;\rm N[/tex]
Hence we can conclude that the net force on the car is 7500 N.
To know more about the net force, follow the link given below.
https://brainly.com/question/14361879.
