Question

You want to predict the frequency at which a spring ball system will oscillate. You measure the spring constant to be 179 \frac{N}{m} âm â âN ââ and use a ball of mass 1.48 kg. The frequency is

Answer 1

Answer:

 f= 1.75 Hz

Explanation:

Given that

Spring constant ,K = 179 N/m

Mass of the ball ,m = 1.48 kg

Lets take angular frequency = ω rad/s

We know that

ω² = m K

$\omega=\sqrt{\dfrac{K}{m}}$

Now by putting the values in the above equation

$\omega=\sqrt{\dfrac{179}{1.48}}$

ω= 10.99 rad/s

We know that

ω = 2 π f

$f=\dfrac{\omega}{2\pi }$

$f=\dfrac{10.99}{2 \pi }$

f= 1.75 Hz

Therefore the frequency will be 1.75 Hz.