Answer:
[tex]Q_1=18.69\\Q_2=22.2\\Q_3=25.7[/tex]
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 22.2 miles per gallon
Standard Deviation, σ = 5.2 mpg
We are given that the distribution of gas mileage is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
First Quartile(Cumulative proportion 0.25)
We have to find the value of x such that the probability is 0.25
P(X < x)
[tex]=P( z \leq \displaystyle\frac{x - 22.}{5.2})=0.25 [/tex]
Calculation the value from standard normal z table, we have,
[tex]P(z<-0.674) = 0.25[/tex]
[tex]\displaystyle\frac{x - 22.2}{5.2} = -0.674\\\\x = 18.69[/tex]
[tex]Q_1 = 18.69[/tex]
Second Quartile(Cumulative proportion 0.5)
We have to find the value of x such that the probability is 0.5
P(X < x)
[tex]=P( z \leq \displaystyle\frac{x - 22.}{5.2})=0.5 [/tex]
Calculation the value from standard normal z table, we have,
[tex]P(z<0.00) = 0.5[/tex]
[tex]\displaystyle\frac{x - 22.2}{5.2} = 0.0\\\\x = 22.2[/tex]
[tex]Q_2 = 22.2[/tex]
Third Quartile(Cumulative proportion 0.75)
We have to find the value of x such that the probability is 0.75
P(X < x)
[tex]=P( z \leq \displaystyle\frac{x - 22.}{5.2})=0.75 [/tex]
Calculation the value from standard normal z table, we have,
[tex]P(z<0.674) = 0.75[/tex]
[tex]\displaystyle\frac{x - 22.2}{5.2} = 0.674\\\\x = 25.70[/tex]
[tex]Q_3 = 25.70[/tex]
Inter-quartile range:
[tex]Q_3-Q_1=25.70-22.2 = 3.5[/tex]