Question

Four pairs of parallel plates are charged. An electron in each pair of plates is moved from the positive to the negative plate.
The table shows the electric field and distance between the plates in each pair.
Pair of Plates
W
х
Electric Field (NIC)
262
256
152
103
Distance (m)
0.026
0.032
0.067
0.043
Which lists the pairs of plates in order from least to greatest in terms of the work done to move the electron?
OW, X, Y, Z
OW, X,Z,Y
O ZY, X, W
OZ, W, X, Y

Answer 1

Ranking from least to greatest work done: Z, W, X, Y

Explanation:

The work done to move an electron between the two plates is given by

$W=e\Delta V$

where

$e$ is the charge of the electron

$\Delta V$ is the potential difference between the plates

The potential difference between the plates can be written as

$\Delta V = Ed$

where

E is the magnitude of the electric field

d is the distance between the plates

Therefore, the work done on the electron can be written as

$W=eEd$

So we can rank the plates by work done by simply comparing the $\Delta V$ between the plates for each case:

W: $\Delta V = Ed=(262)(0.026)=6.8 V$

X: $\Delta V = Ed=(256)(0.032)=8.2 V$

Y: $\Delta V = Ed=(152)(0.067)=10.2 V$

Z: $\Delta V=Ed=(103)(0.043)=4.4 V$

Therefore, the ranking from least to greatest work done is:

Z, W, X, Y

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

Answer 2

Answer:

They are correct. The answer is Z, W, X, Y

Explanation:

Got it right on edge