The golden ratio rho can be defined by lim n → [infinity] bn = rho , where rho = 1 + 1/rho. Solve this equation for rho. (Round your answer to four decimal places.)

Respuesta :

Answer:

[tex] \\ \rho \approx 1.6180 [/tex] (rounding to four decimal places)

Step-by-step explanation:

As a clarification note: The Golden Ratio is usually represented by the Greek letter phi ([tex] \phi [/tex]) and not by rho letter ([tex] \rho [/tex]). To answer the question, we will use the rho letter.

To solve this equation:

[tex] \\ \rho = 1 + \frac{1}{\rho} [/tex]

We need first to rearrange its terms and then apply the quadratic formula for it, since the result of such rearrangement is a quadratic equation.

Rearranging the formula

Then, the equation [tex] \\ \rho = 1 + \frac{1}{\rho} [/tex] can be multiplied by [tex] \\ \rho [/tex] to both of its sides. The equation remains the same in doing so.

[tex] \\ \rho * (\rho = 1 + \frac{1}{\rho}) [/tex]

[tex] \\ \rho * \rho = \rho + \rho * \frac{1}{\rho} [/tex]

[tex] \\ {\rho}^2 = \rho + \frac{\rho * 1}{\rho} [/tex]

[tex] \\ {\rho}^2 = \rho + \frac{\rho}{\rho} * 1 [/tex]

[tex] \\ {\rho}^2 = \rho + 1 * 1 [/tex]

[tex] \\ {\rho}^2 = \rho + 1 [/tex]

[tex] \\ {\rho}^2 - \rho - 1 = 0 [/tex], which is a quadratic equation that can be solved using the well known quadratic formula aforementioned.

Solutions for the resulting equation

A quadratic equation is of the form:

[tex] \\ a*x^2 + b*x + c = 0 [/tex]

And the formula for solving it has two solutions:

[tex] \\ x_{1} = \frac{-b + \sqrt{b^2 - 4*a*c}}{2*a} [/tex]

[tex] \\ x_{2} = \frac{-b - \sqrt{b^2 - 4*a*c}}{2*a} [/tex]

Well, applying it for:

[tex] \\ {\rho}^2 - \rho - 1 = 0 [/tex], we have [tex] a = 1, b = -1, c = -1 [/tex]

Then, the first solution is:

[tex] \\ \rho_{1} = \frac{-(-1) + \sqrt{(-1)^2 - 4*1*(-1)}}{2*1} [/tex]

[tex] \\ \rho_{1} = \frac{1 + \sqrt{(-1)(-1) - 4*1*(-1)}}{2*1} [/tex]

[tex] \\ \rho_{1} = \frac{1 + \sqrt{1 + 4}}{2*1} [/tex]

[tex] \\ \rho_{1} = \frac{1 + \sqrt{5}}{2} [/tex]

The second solution is:

[tex] \\ \rho_{2} = \frac{-(-1) - \sqrt{(-1)^2 - 4*1*(-1)}}{2*1} [/tex]

[tex] \\ \rho_{2} = \frac{1 - \sqrt{1 + 4}}{2} = \frac{1 - \sqrt{5}}{2} [/tex]

But, the Golden Ratio is a positive number since it is a ratio between positive quantities, thus, the valid solution for the Golden Ratio is the first solution. The second solution is a negative number.

[tex] \\ \rho_{1} = \frac{1 + \sqrt{5}}{2} [/tex], which is the exact solution.

Since the question is asking to round this answer to four decimal places, then we have:

[tex] \sqrt{5} = 2.2360679774997896964091... [/tex]

Therefore

[tex] \\ \rho_{1} = \frac{1 + 2.2360679774997896964091...}{2} [/tex]

[tex] \\ \rho_{1} \approx 1.61803398874989 [/tex] or

[tex] \\ \rho_{1} \approx 1.6180 [/tex] (rounding to four decimal places).

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