Respuesta :
Answer:
[tex] \\ \rho \approx 1.6180 [/tex] (rounding to four decimal places)
Step-by-step explanation:
As a clarification note: The Golden Ratio is usually represented by the Greek letter phi ([tex] \phi [/tex]) and not by rho letter ([tex] \rho [/tex]). To answer the question, we will use the rho letter.
To solve this equation:
[tex] \\ \rho = 1 + \frac{1}{\rho} [/tex]
We need first to rearrange its terms and then apply the quadratic formula for it, since the result of such rearrangement is a quadratic equation.
Rearranging the formula
Then, the equation [tex] \\ \rho = 1 + \frac{1}{\rho} [/tex] can be multiplied by [tex] \\ \rho [/tex] to both of its sides. The equation remains the same in doing so.
[tex] \\ \rho * (\rho = 1 + \frac{1}{\rho}) [/tex]
[tex] \\ \rho * \rho = \rho + \rho * \frac{1}{\rho} [/tex]
[tex] \\ {\rho}^2 = \rho + \frac{\rho * 1}{\rho} [/tex]
[tex] \\ {\rho}^2 = \rho + \frac{\rho}{\rho} * 1 [/tex]
[tex] \\ {\rho}^2 = \rho + 1 * 1 [/tex]
[tex] \\ {\rho}^2 = \rho + 1 [/tex]
[tex] \\ {\rho}^2 - \rho - 1 = 0 [/tex], which is a quadratic equation that can be solved using the well known quadratic formula aforementioned.
Solutions for the resulting equation
A quadratic equation is of the form:
[tex] \\ a*x^2 + b*x + c = 0 [/tex]
And the formula for solving it has two solutions:
[tex] \\ x_{1} = \frac{-b + \sqrt{b^2 - 4*a*c}}{2*a} [/tex]
[tex] \\ x_{2} = \frac{-b - \sqrt{b^2 - 4*a*c}}{2*a} [/tex]
Well, applying it for:
[tex] \\ {\rho}^2 - \rho - 1 = 0 [/tex], we have [tex] a = 1, b = -1, c = -1 [/tex]
Then, the first solution is:
[tex] \\ \rho_{1} = \frac{-(-1) + \sqrt{(-1)^2 - 4*1*(-1)}}{2*1} [/tex]
[tex] \\ \rho_{1} = \frac{1 + \sqrt{(-1)(-1) - 4*1*(-1)}}{2*1} [/tex]
[tex] \\ \rho_{1} = \frac{1 + \sqrt{1 + 4}}{2*1} [/tex]
[tex] \\ \rho_{1} = \frac{1 + \sqrt{5}}{2} [/tex]
The second solution is:
[tex] \\ \rho_{2} = \frac{-(-1) - \sqrt{(-1)^2 - 4*1*(-1)}}{2*1} [/tex]
[tex] \\ \rho_{2} = \frac{1 - \sqrt{1 + 4}}{2} = \frac{1 - \sqrt{5}}{2} [/tex]
But, the Golden Ratio is a positive number since it is a ratio between positive quantities, thus, the valid solution for the Golden Ratio is the first solution. The second solution is a negative number.
[tex] \\ \rho_{1} = \frac{1 + \sqrt{5}}{2} [/tex], which is the exact solution.
Since the question is asking to round this answer to four decimal places, then we have:
[tex] \sqrt{5} = 2.2360679774997896964091... [/tex]
Therefore
[tex] \\ \rho_{1} = \frac{1 + 2.2360679774997896964091...}{2} [/tex]
[tex] \\ \rho_{1} \approx 1.61803398874989 [/tex] or
[tex] \\ \rho_{1} \approx 1.6180 [/tex] (rounding to four decimal places).