Question

A tiny object contains 5.54 x 10^12 protons and 4.71 x 10^12 electrons. What is the net charge on the object?

Answer 1

Answer:

The net charge on the object is 0.1328 μC.

Explanation:

Given that,

Proton $P=5.54\times10^{12}$

Electron $e=4.71\times10^{12}$

We need to calculate the net charge on the object

Using formula of net charge

$Q=p+e$

Where, Q = net charge

p = protons

e = electron

Put the value into the formula

$Q =(5.54-4.71)\times10^{12}\times1.6\times10^{-19}$

$Q=1.328\times10^{-7}\ C$

$Q=0.1328\times10^{-6}\ C$

$Q=0.1328\ \mu C$

Hence, The net charge on the object is 0.1328 μC.