Answer:
Alison wins against Kevin by 0.93 s
Step-by-step explanation:
Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration [tex]a_a[/tex], we have the following equation of motion
[tex]s/4 = a_at_a^2/2[/tex]
where s (m) is the total distance, ta = 3 s is the time
[tex]s = 4a_a3^2/2 = 18a_a[/tex]
[tex]a_a = s/18[/tex]
Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration [tex]a_k[/tex], we have the following equation of motion:
[tex]s/3 = a_kt_k^2/2[/tex]
tk = 4 s is the time
[tex]s = 3a_k4^2/2 = 24a_k[/tex]
[tex]a_k = s/24[/tex]
Since [tex]a_a = s/18[/tex] we can conclude that [tex]a_a > a_k[/tex], so Alison would win.
The time it takes for Alison to cover the entire track
[tex]s = a_aT_a^2/2[/tex]
[tex]T_a^2 = 2s/a_a = 2s/(s/18) = 36 [/tex]
[tex]T_a = \sqrt{36} = 6 s[/tex]
The time it takes for Kevin to cover the entire track
[tex]s = a_kT_k^2/2[/tex]
[tex]T_k^2 = 2s/a_k = 2s/(s/24) = 48 [/tex]
[tex]T_a = \sqrt{48} = 6.93 s[/tex]
So Alison wins against Kevin by 6.93 - 6 = 0.93 s