Answer:
[tex]CV_A = \frac{0.471}{7.12}=0.07 = 7\%[/tex]
[tex]CV_B = \frac{1.811}{7.11}=0.25 =25\%[/tex]
C.The waiting times at Bank A have considerably less variation than the waiting times at Bank B.
Step-by-step explanation:
The Coefficient of variation "shows the extent of variability in relation to the mean of the population" and is defined as:
[tex] CV= \frac{\sigma}{\mu}[/tex]
And the best estimator is [tex]\hat{CV} =\frac{s}{\bar X}[/tex]
Where the sample mean is obtained from:
[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And the sample deviation from:
[tex]s=\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}[/tex]
Bank A
[tex] \bar X_A =7.12 [/tex]
[tex]s_A=0.471 [/tex]
[tex]CV_A = \frac{0.471}{7.12}=0.07 = 7\%[/tex]
Bank B
[tex] \bar X_B =7.11 [/tex]
[tex]s_B=1.811 [/tex]
[tex]CV_B = \frac{1.811}{7.11}=0.25 =25\%[/tex]
And the best option for this cas based on the results obtaines is:
C.The waiting times at Bank A have considerably less variation than the waiting times at Bank B.