Answer:
[tex]f=1.97Hz[/tex]
Explanation:
The angular frequency of a mass-spring system is defined as:
[tex]\omega=\sqrt{\frac{k}{m}}[/tex]
Here k is the spring constant and m is the mass of the ball. So, replacing the given values:
[tex]\omega=\sqrt{\frac{193\frac{N}{m}}{1.26kg}}\\\omega=12.38\frac{rad}{s}[/tex]
The frequency is directly proportional to the angular frequency, as follows:
[tex]f=\frac{\omega}{2\pi}\\f=\frac{12.38\frac{rad}{s}}{2\pi}\\f=1.97Hz[/tex]