Question

A projectile falls beneath the straight-line path it would follow if there were no gravity. How many meters does it fall below this line if it has been traveling for 1 sec? 2 sec?

Answer 1

Answer:

Explanation:

In order to solve the problem we will use the following newton's equation of motion.

$S = ut+\frac{1}{2} gt^{2}$

S = ?

u (initial  velocity) = 0

g = 9.8 $m/s^{2}$

For t = 1 s

$s = 0+\frac{1}{2} (9.8)(1^{2})$

s = 4.9 m = 5m.

For t = 2 s

$S = 0+\frac{1}{2}(9.8)(2^{2})$

s = 19.6 m = 20m