Question

Calculate the solubility at 25°C of AgCl in pure water and in a 0.0080M AgNO3 solution. You'll find Ksp data in the ALEKS Data tab. Round both of your answers to 2 significant digits. The Ksp value of AgCl is 1.77 times 10 to the -10.a. Solubility in water:b. Solubility in 0.0080 AgNO3 solution:

Answer 1

Answer:

a) S = 1.33 E-5 M

b) S = 2.21 E-8 M

Explanation:

• AgCl(s) → Ag+  +  Cl

           S            S          S

a) in pure water:

⇒ Ksp = [ Ag+ ][ Cl- ] = ( S )( S ) = S²

∴ Ksp AgCl = 1.77 E-10

⇒ S² = 1.77 E-10

⇒ S = √1.77 E-10

⇒ S = 1.33 E-5 M

b) in 0.0080 M AgNO3:

• AgNO3 →   Ag+    +    NO3-

         0.008     0.008        0.008

• AgCl →      Ag+       +    Cl-

          S        S + 0.008         S

⇒ Ksp = 1.77 E-10 = (S + 0.0080)*( S )

⇒ Ksp = 1.77 E-10 = S² + 0.008S

⇒ S² + 0.008S - 1.77 E-10 = 0

⇒ S = 2.21 E-8 M