Calculate the work done by a person who exerts a force of 200.0 N in the horizontal direction on a box that moves 10.0 meters along a ramp that makes an angle of +30.0o with the horizontal, moving the box at a constant speed. Note: Do not include the work done on the person, only on the box.a. 1000 Jb. 1730 Jc. 3430 J

Respuesta :

To solve this problem we will apply the work theorem, which warns that the energy in a body is equivalent to the Force applied on it by its distance traveled, that is,

[tex]W = \vec{F}\cdot \vec{d}[/tex]

Here,

[tex]\vec{F} = Force[/tex]

[tex]\vec{d} = Distance[/tex]

When you do not have the values of the vectors, but their magnitude the expression can be written as

[tex]W = Fd cos\theta[/tex]

Where,

[tex]\theta =[/tex] Angle between the force and the distance, at this case 30°

Replacing we have that

[tex]W = (200)(10)(cos30)[/tex]

[tex]W = 1732J[/tex]

Therefore the correct answer is B. 1730J.

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