Question

Three 1.0 kg masses are located at the corners of a vertically standing equilateral triangles with sides 0.80 m long. (a) what is the mutual gravitational potential energy?

Answer 1

Answer:

gravitational potential energy = -2.50 × $10^{-10}$   J

Explanation:

given data

mass m = 1 kg

length l = 0.80 m

solution

we get here mutual gravitational potential energy that is express as

As Potential energy between two masses = $\frac{-Gm^2}{l}$   .........1

here is 3 pair of mass so

gravitational potential energy =  $\frac{-3*6.67*10^{-11}*1^2}{0.80}$

gravitational potential energy = -2.50 × $10^{-10}$    J