Answer:
The resultant integer (decimal number) exceeds 3 bits.
Explanation:
The computer program uses 3 bits of the 4 bits of the computer system, counting from the least significant bit.
The decimal number 6 and 2 are "0110" and "0010"respectively, represented by the computer system.
The computer program represents the 6 and 2 with 3 bits from the least significant bit (that is, it counts from the right). so 6 and 2 becomes 110 and 010 respectively.
= 6 + 2 = 8
= "110" + "010" = "1000"
Adding 6 and 2 gives 8 represented as "1000" by the computer system, but the computer program represents as "000"