Question

A bomb calorimeter has a heat capacity of 3.18 kJ/K. When 0.0038 mol of a gas is burned in the calorimeter, the temperature increased from 25.0°C to 27.3°C. Calculate the energy released by the combustion of one mole of the gas.

Answer 1

Answer:

Explanation:

Given

Heat capacity of Calorimeter $C=3.18\ KJ/K$

no of moles $n=0.0038\ mol$

initial temperature $T_i=25^{\circ}C$

Final Temperature $T_f=27.3^{\circ}C$

increase in temperature $\Delta T=27.3-25=2.3^{\circ}C$

Energy released by combustion of 0.0038 mole is given by

$Q=3.18\times \Delta T$

$Q=3.18\times 2.3=7.314\ kJ$

This Energy is associated with 0.0038 moles therefore energy associated with 1 mole is $=\frac{7.314}{0.0038}=1.924\times 10^{3}\ kJ$