Answer:
The spring constant of the spring is 2940 N/m.
Explanation:
It is given that,
Mass of the load, m = 15 kg
The scale gets stretched to 5 cm or 0.05 m, x = 0.05 m
When an object is hung on a spring, the force of gravity is balanced by the force of gravity as :
[tex]kx=mg[/tex]
Where
k is the spring constant of the spring
[tex]k=\dfrac{mg}{x}[/tex]
[tex]k=\dfrac{15\times 9.8}{0.05}[/tex]
k = 2940 N/m
So, the spring constant of the spring is 2940 N/m. Hence, this is the required solution.
