Answer: The equilibrium constant expression for the given equation is written below.
Explanation:
Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_{p}[/tex]
For the general chemical equation:
[tex]aA+bB\rightleftharpoons cC+dD[/tex]
The expression of [tex]K_p[/tex] follows:
[tex]K_p=\frac{p_C^c\times p_D^d}{p_A^a\times p_B^b}[/tex]
For the given chemical equation:
[tex]4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)[/tex]
The expression of [tex]K_p[/tex] for above equation follows:
[tex]K_p=\frac{(p_{H_2O}^5)\times (p_{NO}^4)}{(p_{NH_3}^4)\times (p_{O_2}^5)}[/tex]
Hence, the equilibrium constant expression for the given equation is written above.