Question

Reduce 7y + 2y 2 - 7 by 3 - 4y.

A. 2y2 - 11y + 10
B. -2y2 - 11y + 10
C. -2y2 + 11y - 10
D. 2y2 + 11y - 10

Answer 1

Answer:

D. $2y^2+11y-10$.

Step-by-step explanation:

Given:

We need to reduce $7y+2y^2-7$ by $3-4y$

Solution:

To reduce the equation means we need to subtract the one equation from other.

First we will arrange the equation n proper format we get;

$2y^2+7y-7$  ⇒ equation 1

Also Arranging other equation we get;

$-4y+3$   ⇒ equation 2

Now we will subtract equation 2 from equation 1 we get;

$(2y^2+7y-7)-(-4y+3)$

Now Applying distributive property for the sign we get;

$2y^2+7y-7+4y-3$

Now Arranging the like terms we get;

$2y2+7y-+4y-7-3\\\\2y^2+11y-10$

Hence the reduce form of the given equation is $2y^2+11y-10$.

Answer 2

Answer:

2y^2 + 11y - 10

The answer is D.