Respuesta :
Answer:
5 field goals and 5 free throws were made when season high scored was scored.
Step-by-step explanation:
Given:
Number of points score in every game =3 points
Points for field goal = 2 points
Point for free throw = 1 point
Let the number of the field goals be 'x'.
Let the number of free-throws be 'y'.
Solution:
Now we know that;
Number of points score in every game is equal Points for field goal multiplied by the number of the field goals plus Point for free throw multiplied by the number of free-throws.
framing in equation form we get;
[tex]2x+y=3 \ \ \ \ equation 1[/tex]
Also Given:
Season high score in 1 game = 15 points.
Now the equation will become as;
[tex]2x+y =15 \ \ \ \ equation\ 2[/tex]
Hence the System of equation representing the situation are [tex]\left \{ {{2x+y=3} \atop {2x+y=15}} \right.[/tex] .
Now if we multiply equation 1 by 5 we get;
[tex]5(2x+y)=3\times 5\\\\10x+5y =15[/tex]
Hence from equation we can see that after multiplying 5 on both side right hand side of the equation becomes the same.
Hence we can say that 5 field goals and 5 free throws were made when season high scored was scored.