Answer: 8
Step-by-step explanation:
The degree of freedom for t-distribution of testing the differnce between the two population mean is given by :-
[tex]df= n_1+n_2-2[/tex]
, where [tex]n_1[/tex] = Size of first sample.
[tex]n_1[/tex] = Size of second sample.
As per given ,
Veterinarian selects five horses that are known to have enteroliths and compares the number of flakes of alfalfa they have eaten over a month with the number of flakes eaten by five horses free of enteroliths.
i.e. [tex]n_1=5[/tex] and [tex]n_2=5[/tex]
Now , If she calculates a two-sample confidence interval by hand for the difference in the mean number of flakes fed to horses with and without enteroliths the degrees of freedom she should use are
[tex]df= 5+5-2=8[/tex]
Hence, the correct answer is 8.