A ball is thrown straight up into the air. At each of the following instants, is the magnitude of the ball's acceleration greater than g, equal to g, less than g, or zero? Air resistance may be neglected.
A) just after leaving your hand?
B) at the very top (maximum height)?
C) just before hitting the ground?

g is the gravitational constant, so unless there's air resistance, their magnitude should always be the same no matter whether the ball is just leaving hand, at the very top (maximum height), or just before hitting the ground.

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bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 2 · 2022-01-21T10:05:08+01:00

Acceleration is the rate of change of velocity of a body.

The acceleration of the ball just after leaving from the hand is grater than the acceleration due to gravity g.

The acceleration of the ball at the very top (maximum height ) is equal to the acceleration due to gravity g.

The acceleration of the ball just before hitting the ground is equal to the acceleration due to gravity g.

Given information-

A ball is thrown straight up into the air.

The air resistance is neglected.

Acceleration

Acceleration is the rate of change of velocity of a body.When the ball is thrown vertically upward it starts its vertical motion with an initial velocity.

A) Acceleration of the ball just after leaving from the hand-When the ball was in the hand it was sitting at the rest. Now the ball is thrown straight up into the air thus it must have some acceleration. This acceleration must be greater than the acceleration due to the gravity for the ball to move with the upward force in upward direction. Thus the acceleration of the ball just after leaving from the hand is grater than the acceleration due to gravity g.

B) Acceleration of the ball at the very top (maximum height)-When the ball was at the highest point the speed of the ball is zero. The velocity of the ball is zero but the acceleration of the ball is equal to the gravity force, as only one force is working on it at the highest point.Thus the acceleration of the ball at the very top (maximum height ) is equal to the acceleration due to gravity g.

C) Acceleration of the ball just before hitting the ground-At the point just before hitting the ground, the ball was moving downward like a free falling body. The acceleration of the free falling body is equal to the gravity force as the body is only falling due to the gravity force. Thus the acceleration of the ball just before hitting the ground is equal to the acceleration due to gravity g.

Hence,

The acceleration of the ball just after leaving from the hand is grater than the acceleration due to gravity g.

The acceleration of the ball at the very top (maximum height ) is equal to the acceleration due to gravity g.

The acceleration of the ball just before hitting the ground is equal to the acceleration due to gravity g.

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