Respuesta :
Answer:
The code is given below. The punctuation_chars variable contains a list of punctuation to be replaced by the program
Explanation:
def strip_punctuation(word):
punctuation_chars = ["'", '"', ",", ".", "!", ":", ";", '#', '@']
for ch in punctuation_chars:
word = word.replace(ch, '')
return word
# Testing the function here. ignore/remove the code below if not required
print(strip_punctuation("Hello, how are you. I am good! ,.!#@"))
OUTPUT
Hello how are you I am good
In this exercise, using the knowledge of computational language in python, we have that this code will be written as:
The code is in the attached image.
We can write the python as:
def strip_punctuation(word):
punctuation_chars = []
for ch in punctuation_chars:
word = word.replace(ch, '')
return word
See more about python at brainly.com/question/13437928
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