Question

A scientist dissolves 5 g of potassium chloride (KCl) crystals in a bottle of water until the final volume is 100mL. What the correct way to label the concentration of the potassium chloride solution described in the scenario?

Answer 1

Answer:

The correct way to label the concentration of the potassium chloride solution described in the scenario by (w/v)%.

Explanation:

% (m/v) is defined as the concentration, which is mass of solute present in 100 mL of solution.

$(m/v)\%=\frac{\text{Mass of solute}}{\text{Volume of solution(mL)}}\times 100$

Mass of potassium chloride = 5 g

Volume of the solution = 100 mL

The correct way to label the concentration of the potassium chloride solution described in the scenario by (w/v)%.

The solution will labelled as :$\frac{5g}{100mL}\times 100=5\%$