Answer:
1. Fred starts with 46 cards.
2. Keith's weekly allowance is $6.
3. Each candy bar costs $4.
4. The smallest odd number is 51
Step-by-step explanation:
1. Let Fred had x numbers of cards initially and he adds 8 new cards to this.
So, the final number of cards (x + 8).
Now, his dog has eaten half of his collection and there remain 27 cards.
So, [tex]\frac{x + 8}{2} = 27[/tex]
⇒ x = 46. (Answer)
2. Let, Keith, get x$ of allowance weekly.
So, he left [tex]\frac{x}{2}[/tex] dollars after watching movies.
He also earned $9 and finally, he left $12.
So, [tex]\frac{x}{2} + 9 = 12[/tex]
⇒ x = $6 (Answer)
3. If each candy bar costs $x, then from the conditions given we can write
4x + 4 = 20
⇒ 4x = 16
⇒ x = $4
4. Let the odd numbers are x, (x + 2) and (x + 4)
So, given that x + (x + 2) + (x + 4) = 159
⇒ 3x + 6 = 159
⇒ 3x = 153
⇒ x = 51
So, the smallest odd number is 51. (Answer)
