Question

What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity (i.e., I=10I0)?

Answer 1

Answer:

The sound intensity level is 10 dB.

Explanation:

Given that,

The intensity of sound wave is 10 times the reference intensity

$I=10I_{0}$

We need to calculate the sound intensity level

Using equation of sound  intensity level

$\beta=10\log\dfrac{I}{I_{0}}$

Where, $I_{0}$ =reference intensity

I = sound intensity

Put the value into the formula

$\beta=10\log\dfrac{10I_{0}}{I_{0}}$

$\beta=10\log(10)$

$\beta=10\ dB$

Hence, The sound intensity level is 10 dB.